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The concentration of pollution in a limited space as a room, depends on the amount of polluted material spread in the room, supply of fresh air, the outlets position and construction, principles used for supply and outlet from the space, the fluid flow in the space etc.
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The concentration of a pollution in a limited space as a room, container, tank etc. depends on
The concentration of a polution can be calculated as
c = q / n V (1 - e-nt) + (c1 - c2) e-nt + c2 (1)
where
c = concentration in the space at perfect mix (m3/m3) (kg/kg)
q = amount of pollution added to the space (m3/h) (kg/h)
n = volume changes per hour (h-1)
V = volume or mass of the space (m3) (kg)
t = time (h)
c1 = concentration in the space at start (m3/m3) (kg/kg)
c2 = concentration in the supply fluid (m3/m3) (kg/kg)
If the start concentration (t = 0 ) in the space and the concentration in the supply fluid is zero, the formula can be reduced to
c = q / n V (1 - e-nt) (2)
Note! After some time the concentration in the room will stabilize. The table below shows the value of c when amount of pollution q = 1, and the volume of the space V = 1.
| Pollution Concentration - c (m3/m3) (kg/kg) | |||||||||
| volume changes per hour (h-1) | Time - t (min) | ||||||||
| 10 | 20 | 40 | 80 | 160 | 320 | 640 | 1280 | 2560 | |
| .5 | .1599 | .3070 | .5669 | .9732 | 1.4728 | 1.8610 | 1.9903 | 2.0000 | 2.0000 |
| 1 | .1535 | .2835 | .4866 | .7364 | .9305 | .9952 | 1.0000 | 1.0000 | 1.0000 |
| 2 | .1417 | .2433 | .3682 | .4653 | .4976 | .5000 | .5000 | .5000 | .5000 |
| 4 | .1216 | .1841 | .2326 | .2488 | .2500 | .2500 | .2500 | .2500 | .2500 |
| 8 | .0921 | .1163 | .1244 | .1250 | .1250 | .1250 | .1250 | .1250 | .1250 |
| 16 | .0582 | .0622 | .0625 | .0625 | .0625 | .0625 | .0625 | .0625 | .0625 |
| 32 | .0311 | .0312 | .0312 | .0313 | .0313 | .0313 | .0313 | .0313 | .0313 |
| 64 | .0156 | .0156 | .0156 | .0156 | .0156 | .0156 | .0156 | .0156 | .0156 |
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